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原创作者:柔肠寸断 [3.A.S.T] http://www.3ast.com.cm
6 o" {- W% X% ^1 |, W5 ?原始出处:http://www.3ast.com.cm
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看不懂的直接绕过, v! n( l ?6 f. ^% W
加密前为:hwy123456
, z% e2 F- h9 j# P o5 I加密后为0F9C1C7A2EE76EBB5C1F4D7526CC4F883F4E
" I6 P0 N: R" m1 W( I9 A' D& A1 `. x9 ^6 \: S( Z* H
============================================
3 b$ {& v d0 b, q- `5 r上面是当时自己校内的心情。现在已经解破出来了,分享给大家
6 v M4 K# q' X* |也就不隐瞒大家什么了,这个是国内某知名大学的后台加密算法8 O& N" q! d' O! s/ ~/ _9 P. v! @
以下是RSA算法文件0 K$ B( A- m9 V( |2 J- ?; @ Z
% y i+ e* u1 `8 e6 u
文件名RSA.ASP0 Y1 n! |$ y6 O, e% j
===============================================& B: v: _# f% f* \6 f$ C' Z+ h4 v( C
<% 1 N( E/ T: s6 J1 M3 F' a
Class clsRSA
( f$ L2 s1 V# _( ]% m5 fPublic PrivateKey
( l/ v! t+ n5 C3 b1 }& F* V- MPublic PublicKey 7 ]* H# S7 ~: T9 G
Public Modulus
1 b- d/ T+ X% _3 c2 yPublic Function Crypt(pLngMessage, pLngKey)
6 v( X/ U; W1 S$ SOn Error Resume Next 9 M1 |: T; z( d6 k g! j
Dim lLngMod ! \' ]( q( f g2 X0 [$ N) S
Dim lLngResult
: O4 ]9 h4 R( ^Dim lLngIndex
! L1 V) ]: T9 t5 [( ]8 @8 oIf pLngKey Mod 2 = 0 Then % b4 v8 ~0 k$ f; ?" J+ j0 U
lLngResult = 1
) z) ?* C1 _; I$ I* EFor lLngIndex = 1 To pLngKey / 2
) W$ O5 o* T) J7 R8 j3 `lLngMod = (pLngMessage ^ 2) Mod Modulus
( k4 |* T& ^& }4 R' Mod may error on key generation " o4 D) i0 n- x1 l7 D
lLngResult = (lLngMod * lLngResult) Mod Modulus
3 C x% @! Y/ W% a; ^If Err Then Exit Function d+ }9 M0 b0 p5 G1 u
Next
; _$ ]7 n, T7 W* I" kElse
- {( U1 W! m J2 T- \7 S9 M9 TlLngResult = pLngMessage
; Z3 f3 p% u# x5 z2 p" \. l& DFor lLngIndex = 1 To pLngKey / 2 : ^; t7 S9 T4 ?! U4 F# K! u
lLngMod = (pLngMessage ^ 2) Mod Modulus
# Z8 d' X' F# C5 o8 zOn Error Resume Next
Q2 Q0 N& F) e8 U% M' Mod may error on key generation 1 {' b" x) g R7 ?, ~5 u4 s$ Q* {9 z
lLngResult = (lLngMod * lLngResult) Mod Modulus
: Y5 a4 O4 i" Q6 _0 _2 ^If Err Then Exit Function
8 M* f8 N7 d8 x+ u7 GNext
$ q5 c1 I6 m) P1 C9 n! {End If
8 K/ c/ a* o; nCrypt = lLngResult
' ?: p( [0 {1 s4 o5 H* D. y/ Z* P& k& pEnd Function
) z+ \ a; a4 M# D3 b$ y1 W* X6 a2 B7 N d
Public Function Encode(ByVal pStrMessage)
9 w; @9 w* V# j0 t& o( W( DDim lLngIndex
& j/ o+ R. ?* k" n& J4 b0 _7 ]Dim lLngMaxIndex 2 l9 h) G7 a3 M( x
Dim lBytAscii
. G, I- g& D" g+ @) n7 a$ LDim lLngEncrypted / N# A4 g3 i" f! N
lLngMaxIndex = Len(pStrMessage)
D& F8 J- `- BIf lLngMaxIndex = 0 Then Exit Function 1 a: N7 n( Q1 l G4 {* ~
For lLngIndex = 1 To lLngMaxIndex x2 o# T" r. j
lBytAscii = Asc(Mid(pStrMessage, lLngIndex, 1))
' n0 R O# J: B8 f9 p8 BlLngEncrypted = Crypt(lBytAscii, PublicKey) 8 p9 \# E- [& H' H6 x
Encode = Encode & NumberToHex(lLngEncrypted, 4) 1 T" s8 N& f( T! k7 R! \
Next
8 x/ `. x7 n; ?* S! @End Function ! F2 h- W; j: h# B% y' X+ ^
Public Function Decode(ByVal pStrMessage) 0 ?. Z3 U. v$ R5 A
Dim lBytAscii 9 a0 r! z* H( W( F' b- B$ d7 N
Dim lLngIndex
% B% K& I: d. @7 W' qDim lLngMaxIndex ) H2 N p3 i' |( W( @7 ?" B
Dim lLngEncryptedData
3 m9 e. v3 k( q/ e/ Y1 A, RDecode = ""
- B+ H' s8 `& B4 b* o G7 zlLngMaxIndex = Len(pStrMessage)
! N, r! v! p8 h t6 |% LFor lLngIndex = 1 To lLngMaxIndex Step 4
* ]( m. ]- W0 G; a# e, V4 Z+ hlLngEncryptedData = HexToNumber(Mid(pStrMessage, lLngIndex, 4)) 7 u; M! k7 D1 ?6 @$ `
lBytAscii = Crypt(lLngEncryptedData, PrivateKey) 1 M D* ]3 J! H. B7 O; M: Y
Decode = Decode & Chr(lBytAscii)
5 m6 r/ i% z- p' k; |Next 3 j/ ^2 ^, w7 i" n# L* g
End Function
6 |4 K" b: m; c/ TPrivate Function NumberToHex(ByRef pLngNumber, ByRef pLngLength) 5 H/ q5 X6 Z; N6 n% ]0 O
NumberToHex = Right(String(pLngLength, "0") & Hex(pLngNumber), pLngLength) o4 `: S( y% M P6 s6 r6 o7 F2 |- Y
End Function
, Y; \+ M4 [3 G% C/ J! ~1 h% [Private Function HexToNumber(ByRef pStrHex)
. |% y( c w, ?! o- ?, JHexToNumber = CLng("&h" & pStrHex)
5 h! Y5 x$ A% [. A4 t) h+ nEnd Function . ]& u. Y9 S& B9 o& v# k; K
End Class ' [& V5 k; f/ e
function Encryptstr(Message)
% F5 `( z5 O' hDim LngKeyE 9 @/ P# T' g, r
Dim LngKeyD
! e$ f0 c8 b) j3 C3 ^9 xDim LngKeyN
3 `5 L$ u2 Y. S/ P( FDim StrMessage
6 {$ U$ T. `$ d: O' w) n; wDim ObjRSA 5 o$ z5 V e% t' A: t6 a D( R: i
LngKeyE = "32823" 8 k* t5 O: d. o/ ^# |# H; ^
LngKeyD = "20643"
; F* _( h# m- B+ H( aLngKeyN = "29893"
2 a) n, C1 K8 qStrMessage = Message - P2 ?4 r l% p
Set ObjRSA = New clsRSA ' h$ p1 p3 \- O3 }6 p; H4 s& q
ObjRSA.PublicKey = LngKeyE
+ [6 ~1 H3 j5 e% kObjRSA.Modulus = LngKeyN
9 Y0 z6 f- [5 N$ j/ `, t1 WEncryptstr = ObjRSA.Encode(StrMessage) b1 U/ q* z, D9 U% G" a5 G
Set ObjRSA = Nothing
2 ~ @+ m2 G; ^: Bend function" j' ~# S2 d. q, Y2 E4 x5 A6 j% X0 c4 E
Function Decryptstr(Message) ' I" _6 R7 ~0 W* N1 T1 j* G
Dim LngKeyE
r2 Z4 D; p9 [/ bDim LngKeyD
/ {( k+ \ o7 [ r. @+ r: hDim LngKeyN
0 \* B9 d) D7 @; p! cDim StrMessage
+ A' D; ]: s+ YDim ObjRSA 5 v- f7 Q; S( P2 G
LngKeyE = "32823" 3 M; c* T7 k `1 A
LngKeyD = "20643"
, I" u6 t) z' A2 y$ O2 dLngKeyN = "29893"
% m0 m& n5 l: n- B, b1 {StrMessage = Message
2 e0 n4 [1 |/ P6 ASet ObjRSA = New clsRSA ; P/ t, Y6 i7 Q5 X
ObjRSA.PrivateKey =LngKeyD
. O7 B* |; }6 qObjRSA.Modulus=LngKeyN V+ W/ O& K0 o+ Q; \( c# s2 d
decryptstr=ObjRSA.Decode(StrMessage)
, W& C) i* e9 d. H, l! CSet ObjRSA = Nothing * G% ~9 q( v" J7 k6 H) F2 l4 ~
end function ) Y% e3 C4 H+ J
%>
6 G$ o& a& f; F2 \===============================================& B% |/ c @! U( Q- i- }9 U
- |( T& O7 E, e9 ^% U' c o: H还有一个用于测试这段代码的test.asp! n- n" J) a8 Q
有兴趣的自己搭建个IIS测试下! d0 i/ F9 q# J, {+ T7 \
<!--#INCLUDE FILE="RSA.asp"--> ! P' [( T* X% T
<%
: H4 v x% A& T! A! ? bfunction Encryptstr(Message)
: I3 k& r& _" u V3 mDim LngKeyE : _$ B; B2 k" n5 B
Dim LngKeyD
+ @( o+ V2 H" v) d% ~0 d& mDim LngKeyN
8 O- I# e( _+ _Dim StrMessage
- `6 I; J7 Z% J e' W( H+ k8 P wDim ObjRSA
4 u6 z7 D& C% B& m# r2 lLngKeyE = "32823"
+ p% Z; ] u% q- y$ ELngKeyD = "20643"
' Y6 K3 m$ p( K, ~4 f" @0 YLngKeyN = "29893"
, r5 G9 ^* E' }# fStrMessage = Message
, v6 X" }+ f& m( _) OSet ObjRSA = New clsRSA
0 Z$ Q4 |* q2 [4 U! y; bObjRSA.PublicKey = LngKeyE N. R4 b& O4 {1 F% v
ObjRSA.Modulus = LngKeyN ( ~: M( v2 W# Z* H7 M3 ^/ B1 q
Encryptstr = ObjRSA.Encode(StrMessage)
! }! m) }* S% Q, ^, gSet ObjRSA = Nothing
- G9 X/ w' b/ c& H4 x% o' @6 zend function
0 C- ]( _) m9 Q6 Z1 ?: a1 Ufunction decryptstr(Message) . T5 x! X$ f9 [
Dim LngKeyE ) @- u( B$ N; C: W7 p
Dim LngKeyD
+ d2 y$ | e5 lDim LngKeyN
2 ^! q; s' Y3 `: |! WDim StrMessage . ], L+ r: Z7 E2 V3 o5 }) W
Dim ObjRSA $ c8 k5 x' r& ^, S ~
LngKeyE = "32823" ; G6 n9 D) E# c2 Q+ o
LngKeyD = "20643" - V8 W |" ]- J+ D/ m
LngKeyN = "29893" $ w+ u( ?; I4 r- h' Y
StrMessage = Message
) K8 G) I- P$ T) [2 Q7 B, b7 iSet ObjRSA = New clsRSA 1 z3 R! K" y$ l+ I
ObjRSA.PrivateKey =LngKeyD ' K( Y" G- ]9 D# z# c
ObjRSA.Modulus=LngKeyN , T* ]8 w2 _1 Y3 N6 L# x3 \% ? p
decryptstr=ObjRSA.Decode(StrMessage) 4 B6 t" A6 p7 A
Set ObjRSA = Nothing , e3 d) l: D% m; W9 C' j6 m$ @5 I2 H
end function ! E Q9 S! A/ ]: o$ k' S/ j: G
dim last,first % Y7 |# I5 P! L- O
first="!@#$%^&*()" ; G1 v, Z0 ~, }( P
Response.Write "加密前为:"&first 0 W) B2 Z2 D/ `: E: c
last=Encryptstr(first)
2 T6 Z& m& J, f5 m& A. kResponse.Write "加密后为"&last 2 D! \) B7 {3 }9 Y
Response.Write "解密后为" &decryptstr(last) 0 j5 j. m' w5 B
%> ==============================================
# V: l3 U: A* F5 P: w1 Y2 u剩下的就是字符的对照表了* y- h" o$ V2 g/ Z# L3 @8 ^
===================字符集================; c1 g. B" q# P4 @; o* c
1_____6EBB) \1 N2 B& D5 U- q: e
2_____5C1F: e: i# B) [/ x% C, F' _
3_____4D758 c3 a9 s7 g& n$ G- m1 x3 Q- S
4_____26CC
& K& u( P6 \& @) L5_____4F882 j) T1 Y7 s, X5 Y" @3 R
6_____3F4E; s$ y8 g4 H, H3 E) x7 ^9 w$ ~$ H
7_____0A9D
0 b& \& D; B8 ~! p8_____1A1C
+ T' s: e5 x1 D% A! r2 h I9 j4 ^9_____6D20
4 \" }! X$ |* F/ F0_____1089
5 v4 [2 I) h5 ^a_____0F3E
: y+ s1 u8 D4 n& G6 Hb_____3159
2 Y! V* L5 S, |4 vc_____3517+ S% [( {) B) ~8 I" `+ L: T- _
d_____419C
4 C$ {/ @5 L* f5 ye_____615C) _* H: `; F8 h6 C% | D
f_____556F
% m1 h* I U9 `g_____2B7F
5 I" X" r4 q* qh_____0F9C
! r1 p9 d1 g: o- u* X6 Ci_____00FA8 T) v" `$ y) o( t1 o
j_____5A50
% T1 @6 }2 i; N y# Tk_____2850% ^- q/ \; B( t% `* z9 J
l_____3E7B
4 D- ^2 `1 y" S: t8 Y5 Zm_____71C5
6 \2 L, c8 m" w/ I( {; W# Fn_____1FC8
/ R- k3 \ \ ho_____74C12 B! R( @! X8 @1 W9 z0 w' a
p_____5FB83 ?, I. W- e% {5 h- @$ O
q_____6085
' P1 B. |/ M! `% Ar_____3AC4
# L p# b1 J4 S$ f% Vs_____2F508 h/ ] K8 \6 X3 ]3 l" a
t_____36F8
7 Q" m! z, ?7 Y s. D7 Q. Ju_____7010
: z l) i* Z( \: t! S) Cv_____0B42- k( b% F( p9 c
w_____1C7A
. u& [9 A5 B% H# B! Z0 lx_____16F8
. y: `+ W. j& N. Ay_____2EE7
8 V$ @1 y; }# Iz_____5CF3
/ ^) @# }$ o; R3 S1 n. o$ i5 _!_____6233) z. \0 P' C% F
@_____3A45
1 I8 Y& @& h5 A6 b$ P" E/ i/ ^. s( {#_____22919 W6 Q0 L$ U. a
$_____5D5C
' h! M, ^9 }' I* I x' ?) }: N( D5 [: S%_____09B9$ Q% S( |. K+ T% }' g- z6 ^% U
^_____43EA
9 d) Y. H7 b8 D+ q- g$ z# a- A&_____62B9
/ X0 h& O2 ]6 X* y4 K9 G- S*_____6301
7 Z; [" w( O8 v3 i(_____46595 G( u, C# ^1 ?5 d: z+ u
)_____5C82 |
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