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原创作者:柔肠寸断 [3.A.S.T] http://www.3ast.com.cm
( V1 L7 G8 l' @9 L( n9 D原始出处:http://www.3ast.com.cm
5 j4 z f3 A$ s5 N# s( s0 l( H3 y$ U
看不懂的直接绕过
8 A- F8 Q5 H% \! _! h加密前为:hwy123456
7 @8 h& x9 d. v8 L4 r2 @# h加密后为0F9C1C7A2EE76EBB5C1F4D7526CC4F883F4E5 b- x8 |9 U6 z7 w* i/ V" s
: L1 m8 Q7 F4 s0 ~============================================* A7 Y) X. [" J! P: I/ ^: T
上面是当时自己校内的心情。现在已经解破出来了,分享给大家1 B( H6 f: _: H: z) u; j
也就不隐瞒大家什么了,这个是国内某知名大学的后台加密算法, R( x/ D0 Y! E* \- S
以下是RSA算法文件
# N) [- @' R6 R( ~
; m/ N+ R! |; D文件名RSA.ASP- K4 w2 ~. _8 E5 B# s2 R
===============================================
, U0 `# e K2 x<% " j% c v }9 A2 K: h- c& b8 S7 \
Class clsRSA
% M0 ]5 `8 Q' f; W; b% ~$ }5 TPublic PrivateKey
# [3 [8 V" m0 M! P0 RPublic PublicKey
3 {7 A5 l- X1 C$ DPublic Modulus z1 p j: e# h: o5 o
Public Function Crypt(pLngMessage, pLngKey) 9 f' A9 }+ z% d* ?
On Error Resume Next 9 d/ b4 C5 b& F6 B- r
Dim lLngMod . ^; O5 B1 |/ J
Dim lLngResult
# g6 {6 `" k- K$ ~ jDim lLngIndex : M/ E( m% L& o, F3 e/ X
If pLngKey Mod 2 = 0 Then
/ l5 {& e4 y7 g! a, ?8 ?( v1 ZlLngResult = 1 $ }) M2 r( M/ _2 [2 s) g
For lLngIndex = 1 To pLngKey / 2
m" J4 c H' wlLngMod = (pLngMessage ^ 2) Mod Modulus
5 S) D4 e6 ]' t9 B- [7 @7 t- }* F' Mod may error on key generation
* s8 h: M! J1 a. RlLngResult = (lLngMod * lLngResult) Mod Modulus
' K. V' e$ l' A: K- L: IIf Err Then Exit Function : F {$ D) s0 ~' ?, w
Next / @" \! n+ l1 _/ A3 X
Else
3 A# `( L% E5 |8 v, E0 w" l2 UlLngResult = pLngMessage
/ Z# ]% v* q4 l! E) wFor lLngIndex = 1 To pLngKey / 2
3 a; m/ r! f# E8 c) RlLngMod = (pLngMessage ^ 2) Mod Modulus 9 m" R. }, {. v; D9 m$ i. ]
On Error Resume Next
6 p7 t; P1 [' ^$ |# v% y9 P9 }' Mod may error on key generation
- R0 h4 ?) B$ {) ^% elLngResult = (lLngMod * lLngResult) Mod Modulus
3 j' m6 t; U6 D* [If Err Then Exit Function
: N; n V8 b1 n8 s" ^7 O7 MNext * f* z# F h" H4 ?
End If
3 I! V& u' z& c S' VCrypt = lLngResult
$ O" M8 M8 k5 `3 y" D* F/ qEnd Function
) ~/ x4 d" }6 ^3 f- z* X4 d! J) R
, e3 [0 V) z4 a* K, x! yPublic Function Encode(ByVal pStrMessage) , v% t0 u- H f* B% Y
Dim lLngIndex 0 |3 i# o4 Z3 B9 e+ C
Dim lLngMaxIndex S! H. Y2 i5 F) ~/ h: c9 z# W' n
Dim lBytAscii 8 d9 d0 Y$ p( N1 z
Dim lLngEncrypted
/ [" ~9 ~9 ?" N7 @lLngMaxIndex = Len(pStrMessage) 8 ?5 L! t! l- j- Z0 _# U1 q# `
If lLngMaxIndex = 0 Then Exit Function
; x6 ~& W& _6 O5 d2 K4 I8 _For lLngIndex = 1 To lLngMaxIndex
4 y5 b% s- l- G6 M4 alBytAscii = Asc(Mid(pStrMessage, lLngIndex, 1))
5 I- e- T! L6 e! s) ?% zlLngEncrypted = Crypt(lBytAscii, PublicKey)
" _/ B2 x% K$ J9 pEncode = Encode & NumberToHex(lLngEncrypted, 4) 9 q! y2 ]& u2 H. `: N
Next * E) z* s9 v" Q1 X3 l! @ `7 X$ D
End Function 3 {# Y9 G( D8 [$ f: L9 E7 U2 e( ^
Public Function Decode(ByVal pStrMessage) 6 H1 q# @& p4 N( j
Dim lBytAscii
5 i( p3 X: s" k( d. h% P5 \1 BDim lLngIndex , F. M8 _6 J- y# F/ y
Dim lLngMaxIndex 4 X, v; c% Z _" L+ _/ Z
Dim lLngEncryptedData
1 `) h- ?4 f. j: LDecode = "" 7 D: @% N7 H4 G6 M
lLngMaxIndex = Len(pStrMessage)
; V, P3 h7 N4 V& b2 IFor lLngIndex = 1 To lLngMaxIndex Step 4
* n7 Z* B: Y$ O% E' BlLngEncryptedData = HexToNumber(Mid(pStrMessage, lLngIndex, 4)) 1 K7 t) R& c( T7 @+ k
lBytAscii = Crypt(lLngEncryptedData, PrivateKey) ! d9 |% C# k0 k! |2 I
Decode = Decode & Chr(lBytAscii) 2 V1 H ]) a1 C5 t$ {- p
Next
$ m4 F5 ~4 H; p( u2 AEnd Function ' c" ~: I) x5 |4 g$ R z
Private Function NumberToHex(ByRef pLngNumber, ByRef pLngLength)
9 Z, p% h% Y; A2 INumberToHex = Right(String(pLngLength, "0") & Hex(pLngNumber), pLngLength) - V4 T. L5 m2 \, I$ @
End Function ) Y& U0 g2 E9 p3 b, W) d
Private Function HexToNumber(ByRef pStrHex)
* z1 o+ F4 ^( ?( H$ ^" \HexToNumber = CLng("&h" & pStrHex) . D) |; Y x. a& v4 U2 I2 F/ y
End Function
$ u7 N/ [- d. ]End Class
% x# o/ w- D& S7 P4 s- Mfunction Encryptstr(Message)
# |' I' `# K/ X+ T, K3 K. {Dim LngKeyE 0 ~3 P2 y; `, T6 T
Dim LngKeyD
4 H" y, k$ I, ~: k9 H/ r# r/ FDim LngKeyN # k( O: ~: x( G1 X% x
Dim StrMessage 1 u3 }1 [, m1 _1 X) ~( q. {8 _" \
Dim ObjRSA
, k+ R0 G" e. N( E; I/ JLngKeyE = "32823" 4 ^& f1 e, L' E" O
LngKeyD = "20643"
3 p9 y# Z! @" J8 q1 q8 i. Z5 I9 \LngKeyN = "29893"
8 u5 |+ C! Z6 g IStrMessage = Message
) s" a0 C( o; V' |* O) |" FSet ObjRSA = New clsRSA 6 u( @! Z: [: W% d3 V
ObjRSA.PublicKey = LngKeyE ; y9 |; |; m+ U$ U
ObjRSA.Modulus = LngKeyN
' }' X. a# v R' j# YEncryptstr = ObjRSA.Encode(StrMessage)
! ~8 Y" A( p+ R* N$ g, @6 T' ASet ObjRSA = Nothing % p, j- k# v! v" g& d1 Q
end function1 t# }$ M% C( d& o2 V
Function Decryptstr(Message)
4 k1 g, I* y jDim LngKeyE
0 Y/ Z0 y) {# b' ?Dim LngKeyD ! L" G. S5 r e( h
Dim LngKeyN
/ Z! X% p$ h* d7 qDim StrMessage + ^' `0 e. o& q# H# _
Dim ObjRSA
& w0 h) [! X) [; ^1 Q- kLngKeyE = "32823" ) z8 _! W1 h1 K" b: ?
LngKeyD = "20643"
! s6 m+ g8 D2 ]& u' MLngKeyN = "29893"
, L4 [3 `" q, t& sStrMessage = Message
% B9 z. p' H6 `' E3 c+ kSet ObjRSA = New clsRSA ( ^" N, M. z+ I- h; a1 R
ObjRSA.PrivateKey =LngKeyD
3 M4 I- q1 G' O* iObjRSA.Modulus=LngKeyN - \8 y" y% U9 l2 S/ g2 u% H( S
decryptstr=ObjRSA.Decode(StrMessage)
8 E8 J! B5 N) g% _Set ObjRSA = Nothing " c4 E8 r3 N3 `
end function
& P9 U5 I4 U; e9 a, l%>
) w9 y1 U8 P! o4 M, c( o6 ]1 U=============================================== q$ Q( x, z2 o& X+ N
) s; F4 n1 s+ f/ ~还有一个用于测试这段代码的test.asp
0 Q. D) j6 {" J& j9 C' o2 k3 p有兴趣的自己搭建个IIS测试下
* T7 u M1 n, i) p<!--#INCLUDE FILE="RSA.asp"-->
* L1 e8 h- m8 y. y- s7 y4 @<%
- ^" ^, A$ P3 N! sfunction Encryptstr(Message) 4 W% Z S4 | {8 r2 G
Dim LngKeyE , K% q9 x- m' ]1 n: N
Dim LngKeyD
2 b! d" j' _$ X5 ~Dim LngKeyN 0 R$ ~- r$ |$ g2 j: [3 ~" S* g
Dim StrMessage
7 \! D5 q, Z+ N! f7 H; J: PDim ObjRSA
: |' U( u9 u/ WLngKeyE = "32823"
# b+ H: ~) F& ^& z$ b, W fLngKeyD = "20643" ' }1 R% v8 R- Y' a. `9 M) B" \
LngKeyN = "29893" / S L- ~; N! d6 |: M
StrMessage = Message ; V9 V7 p, g) X" [2 m
Set ObjRSA = New clsRSA ( g1 f F( k3 P2 Z0 k2 l
ObjRSA.PublicKey = LngKeyE + X5 V. w* ^7 }7 Q+ l
ObjRSA.Modulus = LngKeyN
4 v. q4 X8 u" a" \3 ?' {Encryptstr = ObjRSA.Encode(StrMessage) / P" ?+ \3 g6 F
Set ObjRSA = Nothing
5 o& f. Z D& z) g* Xend function $ G* C! @, C. y e3 S2 @
function decryptstr(Message)
6 a; {1 c# m2 k0 Q) u( m {) ~ Z( u2 ]+ \Dim LngKeyE
4 P3 e8 {! h$ _! M& Q6 b; g7 N0 W! jDim LngKeyD , s+ D7 ~1 I6 ~! ?! ?" V
Dim LngKeyN
- a8 T S8 s/ k3 xDim StrMessage
) V7 u. t* i$ ~- V9 t* i& p, JDim ObjRSA
+ l+ }4 V3 B' r, P& A6 mLngKeyE = "32823" " Y& H7 j' f0 a, z( d6 d; x8 c
LngKeyD = "20643" ; ?* N. V5 T0 h( s) q& K6 ]2 o, u
LngKeyN = "29893"
7 v. U8 z+ t9 x: |* NStrMessage = Message
. m9 f) |# I1 s4 ?# k, k# ?Set ObjRSA = New clsRSA
1 d6 K/ ^% Z; l# @& D7 |ObjRSA.PrivateKey =LngKeyD
w3 k- ~6 T$ X2 HObjRSA.Modulus=LngKeyN ' y7 J) a6 `( {2 y
decryptstr=ObjRSA.Decode(StrMessage) + Z& p: S: l1 b q
Set ObjRSA = Nothing
! b( S( V: Y6 Y* nend function # L( D! u+ P1 x+ ]) L
dim last,first 6 e9 z0 f7 d: K; y" U6 y8 O
first="!@#$%^&*()"
9 c& _1 q+ X% l1 S% A `# t6 AResponse.Write "加密前为:"&first $ n: W$ D3 k5 }- O. [4 m
last=Encryptstr(first)
) ]' |$ e5 M- D0 tResponse.Write "加密后为"&last
9 O/ Q" g, h2 S: n* R3 \Response.Write "解密后为" &decryptstr(last)
/ a2 z: d( _- q* B%> ==============================================
' F. P' G; Q1 W! ?. F+ T. l剩下的就是字符的对照表了" }( S3 C7 K% |/ g# ]# F
===================字符集================
( T$ i; m9 r1 s5 }1_____6EBB
; V' U" j, n8 A- ~2_____5C1F
6 p6 N$ T2 [& r3 z! c5 ~9 s3_____4D75, y$ R; @( k$ ]
4_____26CC Y' J e8 j" g, [9 \) {+ H' x
5_____4F88
& e, t1 ^+ ]9 h. G+ q. f6_____3F4E
$ F/ q2 }- b- T# p4 t$ ^7_____0A9D6 v" Y; e% }$ d0 I( }% w* x
8_____1A1C* T, o1 t1 i' ?) |; \
9_____6D204 ~% A: }& i* R. T
0_____10891 o' ?* R5 X- t, E8 |/ ^. H
a_____0F3E
$ C% T2 F7 [ o/ [* hb_____3159
* z3 D; \6 W; k% nc_____3517
6 J6 t: f. U+ K5 n- p8 [d_____419C! ^6 d2 L3 A2 g; O" j! e. J$ A
e_____615C
& D( m: |/ Q0 t! N* U: M! Zf_____556F
+ P0 E J+ W# c" u' v, xg_____2B7F
- v: U. o7 H4 t1 A; `* u4 ^0 w `h_____0F9C
1 x5 S" A7 b; n; h! Wi_____00FA
( z2 S. O# A, {0 i8 A/ I4 zj_____5A50# z! }: b6 ?6 \1 I7 U3 L, j# G
k_____2850
' m" R' a' r6 I3 Fl_____3E7B
' ^8 t6 K2 t& \) D0 J: c9 K& Z! Km_____71C5
- {, f- U4 z- s2 Q" w7 ~n_____1FC82 S7 S. P; ?* _, w7 S
o_____74C1
1 [) t$ o3 o r fp_____5FB8+ c0 u5 c$ r, d, h* O
q_____6085
1 C! M. t: ]4 I/ R: ~! m8 cr_____3AC42 c: d! ^5 \, m* X$ T7 H) ?1 R
s_____2F50
5 f3 ~4 \1 ?' K5 k/ L* Bt_____36F89 ^4 i. K- [' F8 Z6 V3 t8 W* d
u_____70109 S B! J. K; }9 A" w# U4 D5 h* d
v_____0B42
9 u+ Q8 X% ~$ c D J* ow_____1C7A& H; s+ o8 |: P5 L6 x, D
x_____16F8! \. V+ p: C% H
y_____2EE7
! N- H; b0 \# k2 j6 o3 Az_____5CF37 X6 n) i- e2 u. k. {/ }
!_____62330 R5 o# q0 q- w1 q |
@_____3A45& A7 \# @& R( U. M1 i
#_____2291 a6 i+ v6 J" P! z1 ]5 j/ M. N
$_____5D5C+ O0 g2 t9 Z q# P8 \7 R
%_____09B97 `* M3 W: H9 d; @
^_____43EA
; t" a# T$ f+ V* H, W; R# u& F( A+ d. U&_____62B9
1 F5 C# X1 G5 N' l$ x6 a*_____63016 `+ T) u9 y% ?- b/ k+ ^. ^) q
(_____46597 Y" ^1 l4 ^" C0 X5 \
)_____5C82 |
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