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原创作者:柔肠寸断 [3.A.S.T] http://www.3ast.com.cm, D* N4 A4 T4 o3 w, D$ y7 k0 @8 x. d7 {
原始出处:http://www.3ast.com.cm1 v9 H. e6 G5 D9 w
* J& y+ A3 T0 l2 n( R7 I Y, z
看不懂的直接绕过5 z7 E" p) m; L( n
加密前为:hwy123456. S7 X$ ~" v7 O. a3 G# U# b
加密后为0F9C1C7A2EE76EBB5C1F4D7526CC4F883F4E: ~ j% [( x9 ?5 N, L! p
& K! u7 V0 m( r; d {! j$ W, ^/ L============================================9 Y8 J* z0 R8 K1 z9 e( C6 {/ _0 p
上面是当时自己校内的心情。现在已经解破出来了,分享给大家
1 i% g; C$ V6 |8 [1 ]9 `; K也就不隐瞒大家什么了,这个是国内某知名大学的后台加密算法
1 b/ p5 B& H1 m以下是RSA算法文件# I! S; B8 G% N% \! S
9 L9 z$ b0 z! m0 m8 ]/ J4 D文件名RSA.ASP2 ?, e4 z& k& g" t& i L
===============================================4 R; B; O- M3 J
<% 2 w$ Z% m& p8 e; T6 n ?
Class clsRSA ' q% v4 t: u* M& W
Public PrivateKey
3 I. _6 j3 D$ o- q! l* w( g1 \6 C0 ~Public PublicKey
' q* F4 h: d$ \" A0 g: r" J8 {7 BPublic Modulus 3 g, F, ]0 b( }( ]7 R9 d
Public Function Crypt(pLngMessage, pLngKey) 9 J3 ^: P% D/ i( Q+ N& c) L
On Error Resume Next
' b! Y: Z1 {# bDim lLngMod # S. g4 g7 t% }
Dim lLngResult ( s# h7 l; i @7 U( I
Dim lLngIndex
Z* e( O2 U) ]5 MIf pLngKey Mod 2 = 0 Then # ]0 ~& f. w; d7 C( D8 Y1 @( b( M' y
lLngResult = 1
) @' Z/ f8 C; Q' i7 k+ E' \7 H0 ZFor lLngIndex = 1 To pLngKey / 2 a {. b4 @" Q2 U$ X
lLngMod = (pLngMessage ^ 2) Mod Modulus
/ t4 c# f) i _( ? I, _$ F+ c' Mod may error on key generation
( g0 j3 d& R! H ClLngResult = (lLngMod * lLngResult) Mod Modulus & a h8 d# I3 Q: }8 w2 U% G$ x
If Err Then Exit Function ( L# a }( ], I: s
Next . f5 l( z: M7 p, N
Else / T' c# G! C, c0 P; G5 T: S: X
lLngResult = pLngMessage " U( o7 I8 s& M5 n9 W& Z9 M
For lLngIndex = 1 To pLngKey / 2 # y0 p0 w+ }/ H- f9 ^$ ^* c
lLngMod = (pLngMessage ^ 2) Mod Modulus
3 K, q+ @7 v5 ?" {6 VOn Error Resume Next v: G% O! n% H- O$ o9 y( x
' Mod may error on key generation
, R( r2 \# E/ f2 S, |) `lLngResult = (lLngMod * lLngResult) Mod Modulus
e# p: d7 O9 l4 r j4 C# xIf Err Then Exit Function ' ~) A8 ]4 O4 E$ T% }) f
Next
& K+ \$ s# h: V3 \& \- G) X: ZEnd If
7 C5 G: j* [, w4 A9 L+ M5 ?Crypt = lLngResult
; i4 E0 _+ K! I/ D( M$ g# UEnd Function
4 B/ q% g" w7 u. ]
9 c; V- W! l1 Y4 g2 hPublic Function Encode(ByVal pStrMessage) % @! b O: F* }* [
Dim lLngIndex
# K- u4 N" v6 ?" l) @Dim lLngMaxIndex 5 Z1 d |1 `3 R1 }9 S8 d* y
Dim lBytAscii
- o& D& m8 r! Y' o- W8 j7 p- X1 h$ {- BDim lLngEncrypted
- X: k! D" Y, e( D* E6 X2 [ {lLngMaxIndex = Len(pStrMessage) ' p& C1 q' X9 g5 o! { K
If lLngMaxIndex = 0 Then Exit Function ( ?$ r9 I8 q- P8 [
For lLngIndex = 1 To lLngMaxIndex # K% ~. r% k" G
lBytAscii = Asc(Mid(pStrMessage, lLngIndex, 1)) ' ]" S8 t9 P2 \% q) i8 {
lLngEncrypted = Crypt(lBytAscii, PublicKey)
1 l, j# p& Z2 d3 F' PEncode = Encode & NumberToHex(lLngEncrypted, 4)
+ z; C% ^ g8 B% I3 vNext / V& i' W4 Z, `; Q+ q/ {3 r: M: g# N, i
End Function
2 f5 \) _+ O j' mPublic Function Decode(ByVal pStrMessage)
: k7 F1 f" }# w* w3 V$ S$ cDim lBytAscii
5 i/ ^. F# g. p- s1 i% QDim lLngIndex - b: f X$ K" O0 F( o2 [' |
Dim lLngMaxIndex 9 c* n3 s3 X) r( r
Dim lLngEncryptedData
: |1 Y2 }2 W* C) ?4 b5 iDecode = "" 5 J/ e- E" n w4 r7 E! N$ _' k
lLngMaxIndex = Len(pStrMessage) * }* h/ A% W% \- |, f& l1 a$ w
For lLngIndex = 1 To lLngMaxIndex Step 4 ! [% C S9 i$ @" z
lLngEncryptedData = HexToNumber(Mid(pStrMessage, lLngIndex, 4))
! `7 E& D5 o* JlBytAscii = Crypt(lLngEncryptedData, PrivateKey)
' l4 @* b9 x, W' m7 S" D; F% aDecode = Decode & Chr(lBytAscii)
" h; B4 w3 G% P3 l* P" i( ?% @2 HNext
; J% q- b$ A3 x1 DEnd Function
" v5 ~% k% t/ m! JPrivate Function NumberToHex(ByRef pLngNumber, ByRef pLngLength) / ]# w5 p+ |' i+ |
NumberToHex = Right(String(pLngLength, "0") & Hex(pLngNumber), pLngLength) - P) ~# w1 _6 \0 k% P
End Function
2 V1 ~* f! m6 k. X$ nPrivate Function HexToNumber(ByRef pStrHex)
z6 [3 }. W4 v% K5 O1 r0 }9 jHexToNumber = CLng("&h" & pStrHex)
0 N& I% u% {' WEnd Function 0 V' V5 f, n& q% l
End Class
4 V* F4 Z9 p+ R, qfunction Encryptstr(Message)
6 k1 _. m$ S, i" dDim LngKeyE
0 P' |( q( q6 B1 a- o4 `Dim LngKeyD
/ O( m. Q" i8 F e1 EDim LngKeyN & K9 B# S5 d$ p0 k( B
Dim StrMessage
C2 j; G9 ~# ~( @9 t4 i+ t. |Dim ObjRSA " m" a* E4 v5 k( C0 ?/ ^
LngKeyE = "32823"
" f4 T8 k6 j7 E; u- U+ xLngKeyD = "20643" 0 S C! T [9 r/ q2 E9 j
LngKeyN = "29893" 8 U |- Z3 A3 j5 b# U: ]
StrMessage = Message % Y( s" `0 A+ |; z M' O
Set ObjRSA = New clsRSA
/ N- s2 }1 Y6 tObjRSA.PublicKey = LngKeyE
4 ?+ [" c' f% [8 [4 y ]ObjRSA.Modulus = LngKeyN
! B3 W4 K; ^6 h* N( gEncryptstr = ObjRSA.Encode(StrMessage)
6 O/ Z5 _& z& n- E6 gSet ObjRSA = Nothing 8 i+ @' r1 |8 F
end function
$ P$ D9 u) R. D) G( ?# yFunction Decryptstr(Message) # a& c3 [& n; i& Y
Dim LngKeyE % |$ o: Y, O% i0 [& ]* B* k
Dim LngKeyD 1 Y+ k' z) X4 s( F
Dim LngKeyN
8 E8 s, Y1 G8 a+ P& cDim StrMessage
# Q# y" F! i# S( v# R# hDim ObjRSA 9 e' }. Z0 o* L& r5 R6 X
LngKeyE = "32823"
5 k; \* r/ ]; A1 hLngKeyD = "20643"
8 n/ Z4 |9 o+ c; {! Q; y* G: @LngKeyN = "29893" ) e7 e5 R5 p8 l, {) j9 b
StrMessage = Message 6 S* Y9 D- J# u2 W
Set ObjRSA = New clsRSA
6 ]( Z* F& A9 M5 c# TObjRSA.PrivateKey =LngKeyD ' h. k0 f, L$ W1 M; E
ObjRSA.Modulus=LngKeyN 3 F& h3 B- p) P
decryptstr=ObjRSA.Decode(StrMessage)
0 S7 o2 v1 r9 U' o$ Y; gSet ObjRSA = Nothing
* o3 Z1 a2 T+ Q5 G) F4 Tend function - q& l8 |5 t) u- D' t; t: ?
%># ~$ k3 F+ O4 a
===============================================
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还有一个用于测试这段代码的test.asp
' ]' a t3 `; }. ~! \$ j" y有兴趣的自己搭建个IIS测试下
) T% J9 l. J" F8 c1 V<!--#INCLUDE FILE="RSA.asp"-->
# P9 h. [' ]' |9 j<%1 K9 |9 ~2 T8 s
function Encryptstr(Message)
) l( |6 b/ L2 k8 d UDim LngKeyE 3 `1 j# K+ c0 J) {* m- `
Dim LngKeyD ) k& Z6 M1 j0 S- W
Dim LngKeyN 5 ]; X$ s8 g. t) F* s$ V; F7 D, e
Dim StrMessage 7 V2 H' W2 p! H
Dim ObjRSA
* @' q- _" q: H% N8 xLngKeyE = "32823"
5 g9 H6 {: l* `! N" @7 e9 xLngKeyD = "20643" 7 a; R8 A [0 }- G& |* d
LngKeyN = "29893"
$ z0 M" w8 N; H e" {StrMessage = Message
! |; r' r' \0 T1 |( X7 ], ]# G/ HSet ObjRSA = New clsRSA 7 `! Z8 S r4 z. K! s' l/ o
ObjRSA.PublicKey = LngKeyE
1 u7 i! H- L$ ~; ~6 c0 f0 P2 rObjRSA.Modulus = LngKeyN
( q, v/ U1 I3 T4 S! M0 k! @Encryptstr = ObjRSA.Encode(StrMessage)
4 ^/ g# I: y5 ~* ^Set ObjRSA = Nothing
0 k+ t: m, J+ aend function 2 T9 U' `) c3 S9 V
function decryptstr(Message) 8 L; W5 }+ [1 G5 b j
Dim LngKeyE
# Z. h, K2 ~- I: X9 zDim LngKeyD
+ Z$ u$ O( K( f) q# e4 |( NDim LngKeyN 4 f: M. L0 ~, D! ~6 N
Dim StrMessage & i( Y) v/ F# N" J4 q# |# [+ r
Dim ObjRSA z+ w7 T, z" t% H4 `
LngKeyE = "32823" + ^4 t! T$ ?8 _0 v9 U" j
LngKeyD = "20643"
9 m# x9 `! e$ S1 ~5 mLngKeyN = "29893" 6 z! f, v8 ^7 v; F: N6 z" m$ r
StrMessage = Message
8 y( X3 V# w' ~2 {9 WSet ObjRSA = New clsRSA
* s& p8 B, S7 ?# I, u, `ObjRSA.PrivateKey =LngKeyD # L g$ J6 ~1 M" h2 P
ObjRSA.Modulus=LngKeyN
- D: U0 Z& p! \0 f8 A R' b* pdecryptstr=ObjRSA.Decode(StrMessage) ! r2 p3 W7 [; j+ a" ]
Set ObjRSA = Nothing / Y- C" u* X0 r7 M E7 j
end function
' y; e4 r! l+ v/ ^. b( xdim last,first
0 m% X. v0 [/ f( ~' k: h% g$ ffirst="!@#$%^&*()"
" w) s. r7 x5 S5 ]$ G5 b0 jResponse.Write "加密前为:"&first
2 E4 i$ e, [3 D; j. Q4 jlast=Encryptstr(first)
& @! _2 @" Z' W: R# I5 eResponse.Write "加密后为"&last
7 A8 ^* x* `+ t, l2 L; [7 J; t/ zResponse.Write "解密后为" &decryptstr(last) : z3 s" M% k7 x1 ~+ L0 w+ h/ }2 {: s
%> ==============================================1 s" k5 Q4 j% t- x4 F' H0 Z
剩下的就是字符的对照表了2 p) c$ D7 }; K2 H& p, [7 B0 n
===================字符集================
6 V; M: E" L. t3 s6 R* p% C8 O1 _" r1 G/ k1_____6EBB
8 j- x: H% J: U) e5 j8 S2_____5C1F
$ @3 Z& v5 a0 S) S3_____4D75
4 s4 v9 K# A$ B k5 a5 A4_____26CC
( g; Y6 g& ?2 j" l- U5_____4F88
( e% Z' q0 [% }! T1 V9 j# O7 [. n6_____3F4E
+ M B- p5 z' E: @) l* u7_____0A9D+ A [( g6 ^0 H* [6 `
8_____1A1C- D3 a% P8 Y7 _4 _2 k0 t1 M+ F6 D) @" h
9_____6D20+ \7 y/ M D! o: z. ~
0_____1089
9 Y* e1 t: B7 x5 H; d" ua_____0F3E
i8 r$ A5 D, N: ~b_____3159
% ?6 t5 _$ o1 x' P; nc_____3517
4 o- K, k5 F7 w/ Zd_____419C6 m, Q' w' i- w9 E5 z
e_____615C
6 b* J3 j! t- h# ^2 Qf_____556F9 a$ |5 t: x5 o
g_____2B7F
6 j" f5 N4 Z1 c- `6 P+ qh_____0F9C
& _5 }( s0 Z! a/ G* T6 {( Y5 _i_____00FA
: `+ V+ W/ T! @6 [/ g" \5 Z; wj_____5A505 h% u- [0 w3 t8 ^5 J) X2 I# L
k_____2850
6 Y( m( N. ^/ N3 h8 N) V8 A& ?# Tl_____3E7B
A& ^( a1 \/ t8 ]0 a" Qm_____71C5 v7 j+ s" v9 ]/ x3 W+ }. y, J N
n_____1FC88 R6 [. ]! O) l+ w4 o; Q
o_____74C1
8 t" n. B3 e8 ?1 L! r7 A+ |p_____5FB88 T7 r) {" H; z T. G, K& W" y0 f& n6 `
q_____6085
! R2 s! \& C$ zr_____3AC4+ U1 b9 X. W) }8 h
s_____2F506 o& ?/ B0 D3 h/ |5 D
t_____36F84 F2 a- C. {- Z. X+ \: E8 }
u_____70108 s; g: n+ B4 U9 J- o
v_____0B425 ^3 L# L/ B) e3 i9 _; T4 U
w_____1C7A
5 `1 l% j4 i- D5 Hx_____16F8) l7 @/ t5 ]% w. e( m
y_____2EE7
3 L8 Q: h- y$ t( t1 [* O# iz_____5CF3( V# G. s/ w0 Q2 `* n# e3 a
!_____6233
/ ?5 U3 p, x2 l@_____3A45# o' Q9 @# w2 r$ B3 P- m4 }, J
#_____2291' z: @+ T' E" j3 D3 R
$_____5D5C
1 |2 m! |8 U+ w) v%_____09B9+ ~7 J* F+ f- `- v5 K
^_____43EA
) j& Z# Y2 T6 A- W/ u2 Z&_____62B9+ W$ Y2 t/ Q9 Q& c: G
*_____6301
; y1 T! A# u9 {# L(_____4659) h4 M8 E, Q3 r6 C3 p( l
)_____5C82 |
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