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原创作者:柔肠寸断 [3.A.S.T] http://www.3ast.com.cm
8 o: M; B7 f9 K. Y& L; h原始出处:http://www.3ast.com.cm/ ^3 J$ o/ [. N ]4 V, B
% K% F9 p! f6 m! L" l看不懂的直接绕过- I5 i- P7 }7 _' l6 @
加密前为:hwy123456! {6 M2 o q6 K6 y
加密后为0F9C1C7A2EE76EBB5C1F4D7526CC4F883F4E
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============================================' f1 F2 L7 {8 X1 u+ k& \. M
上面是当时自己校内的心情。现在已经解破出来了,分享给大家/ x# l+ J. A4 l; l$ y' ^
也就不隐瞒大家什么了,这个是国内某知名大学的后台加密算法4 R9 l1 }2 }8 N* k3 p
以下是RSA算法文件) I, l. e: p6 l+ `# ~# L
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文件名RSA.ASP" T5 `: t, P( o6 m' k1 ?
===============================================' s$ [: _, e6 s
<%
: C- A6 j" L* y, [5 FClass clsRSA
' |; t/ x9 V5 t* CPublic PrivateKey # [1 b( _* m) {* v) s& f' p
Public PublicKey 5 |7 N0 k. }0 D7 q
Public Modulus
" Y- E; P# \! lPublic Function Crypt(pLngMessage, pLngKey) * W0 \, v' E) p5 q7 e7 ^
On Error Resume Next " m. W$ v2 q" ?; V* _
Dim lLngMod
7 F# F4 t! L- R1 n/ c$ ~8 V6 DDim lLngResult V# I: m% G9 G
Dim lLngIndex ) ^: ^0 n5 i5 f
If pLngKey Mod 2 = 0 Then : J! {, j* L& d9 M
lLngResult = 1 - {3 Z- _$ i, Q( w7 i. r8 q
For lLngIndex = 1 To pLngKey / 2 9 P Y% p& h m/ T( T |: B( f
lLngMod = (pLngMessage ^ 2) Mod Modulus 5 ?5 w2 ?' O, p' g0 e7 m6 b( B5 K
' Mod may error on key generation + I1 [9 G& u6 p" h9 L& O! _
lLngResult = (lLngMod * lLngResult) Mod Modulus / y; r2 w" V8 K
If Err Then Exit Function # [8 E0 p$ `4 V3 z8 m) m* c
Next
/ u& E9 e2 w; D2 c5 UElse
) ~9 R9 M5 ^* b7 W1 F( M6 y0 WlLngResult = pLngMessage $ G- O/ Q5 K* F' y. q( D9 p0 F
For lLngIndex = 1 To pLngKey / 2
+ C2 S; I. o# w4 j- m# alLngMod = (pLngMessage ^ 2) Mod Modulus
0 M, j1 U0 L2 J4 oOn Error Resume Next 4 } l& Y7 }, Y6 e" i6 G5 T5 u
' Mod may error on key generation & {5 g4 B: D/ C/ k/ v* N
lLngResult = (lLngMod * lLngResult) Mod Modulus * @3 `/ B4 a& |: g
If Err Then Exit Function
& H; O8 I4 X! S; v, n$ P+ l' qNext ; T& Q( Z% |' o# S: ^' j5 w
End If 3 K$ v' @( Z+ Y8 A
Crypt = lLngResult
' x; |. x# ?9 z9 G' wEnd Function* E. [# C/ D G7 ~8 t
x# V7 z; w: S/ O) u+ m/ fPublic Function Encode(ByVal pStrMessage) " G8 P, ~0 t' }% ]& ^
Dim lLngIndex
6 {- C& r5 S5 i, v Q" cDim lLngMaxIndex 3 l D, x0 |0 {4 a- A2 I
Dim lBytAscii
2 u1 z( l+ A M, ]: |" Q1 ]Dim lLngEncrypted
' i* ?) ?. Z5 Q m6 T3 o9 r% `9 Y. _lLngMaxIndex = Len(pStrMessage) : u s& z! r. J4 F; w9 T* a
If lLngMaxIndex = 0 Then Exit Function
4 \) s D7 v, K! y5 C$ n! ~For lLngIndex = 1 To lLngMaxIndex " f% `2 t8 F( ]2 {8 j. N* h
lBytAscii = Asc(Mid(pStrMessage, lLngIndex, 1))
3 I3 N; D% v: P6 Z# m* P% ^ xlLngEncrypted = Crypt(lBytAscii, PublicKey) " L) Y3 k: _1 r' n8 ?0 X+ D
Encode = Encode & NumberToHex(lLngEncrypted, 4)
6 W% |# \( e/ H) Y; R2 z6 CNext
; U8 W2 T% U+ ]2 Z4 REnd Function ' u5 G) r) \5 U4 i/ a# h; e( _' T
Public Function Decode(ByVal pStrMessage)
2 z" v2 ~* z. t6 WDim lBytAscii ^; o9 J+ }4 D) L0 L( x+ _
Dim lLngIndex 7 V+ V4 Z/ V3 A7 Z
Dim lLngMaxIndex
# v4 t( V) b% ^8 S4 M" oDim lLngEncryptedData - Z/ a' T; V% f ]9 Z
Decode = ""
- `( v2 G$ v" L. Y) ClLngMaxIndex = Len(pStrMessage)
# o- G7 k5 J, F! W; FFor lLngIndex = 1 To lLngMaxIndex Step 4 8 e7 a$ O, K' J
lLngEncryptedData = HexToNumber(Mid(pStrMessage, lLngIndex, 4)) ' R: u2 l+ B2 ^& J2 H" i1 c
lBytAscii = Crypt(lLngEncryptedData, PrivateKey) ; B' j& N- C: C0 G% e+ B/ |6 P
Decode = Decode & Chr(lBytAscii) " I: I1 ?* o& ~4 i* e
Next # R" Q, y2 D. c3 q
End Function
3 B1 m& S U) w4 X0 n4 k6 CPrivate Function NumberToHex(ByRef pLngNumber, ByRef pLngLength)
{) ]% ^* a# E9 P$ eNumberToHex = Right(String(pLngLength, "0") & Hex(pLngNumber), pLngLength) 5 [& M& k7 A }" q
End Function
! e- L6 @4 d4 e5 OPrivate Function HexToNumber(ByRef pStrHex) ; a5 v3 X) M) E1 ]/ i
HexToNumber = CLng("&h" & pStrHex)
* J6 y; v3 h) ~$ x3 y. G( U2 vEnd Function
0 m% p9 b( A( X( }) O/ o* y) q CEnd Class
- a& p# I! o1 Gfunction Encryptstr(Message)
. M6 G0 K9 Q+ A1 G% }' HDim LngKeyE 4 O! @( P, o9 `2 u4 Q
Dim LngKeyD ' P8 X q' u: H8 e" _1 c0 {" G3 l
Dim LngKeyN & H- X2 F0 P6 R* M a0 ?
Dim StrMessage
( n" G" g6 S" y+ _0 H0 V3 g) vDim ObjRSA 5 h- J; ~) I- f: p& }
LngKeyE = "32823" , {) Q; T* u# P( D! N5 w8 Z
LngKeyD = "20643" U7 c6 E% k: n8 C" ?; p
LngKeyN = "29893"
3 J) k$ D6 v. v& I w$ PStrMessage = Message
9 \* l2 c+ ^, t* x" RSet ObjRSA = New clsRSA
0 c2 t1 [ R. ]ObjRSA.PublicKey = LngKeyE * G: C& J, u/ [. M4 Q
ObjRSA.Modulus = LngKeyN 3 b/ W. |8 T$ }5 p
Encryptstr = ObjRSA.Encode(StrMessage)
7 I7 _' y/ T1 W9 sSet ObjRSA = Nothing
) f1 B u% d! qend function
, O7 @3 ?% q" \4 H6 Z d4 W+ DFunction Decryptstr(Message)
3 h9 d& N7 N& V" j1 K, i0 S8 VDim LngKeyE
4 s, v0 x' g: f7 T" LDim LngKeyD
+ a7 z/ E) T) A; d5 p0 M1 b0 YDim LngKeyN j8 _: H9 v; P$ Q# L
Dim StrMessage
2 n, N8 G3 G( @' B1 Y* ODim ObjRSA
6 C% A5 y L. k% r5 G6 ~. }( @9 c# ~LngKeyE = "32823" - v. C0 d- G/ N) k' M. g
LngKeyD = "20643" * a/ q. a n% p+ G) r
LngKeyN = "29893" 9 ?8 g( s8 |6 R
StrMessage = Message
! ^7 j/ M/ h6 hSet ObjRSA = New clsRSA 9 T4 s" K* J& V4 w% K
ObjRSA.PrivateKey =LngKeyD
' U' U, G" N6 Y6 e3 bObjRSA.Modulus=LngKeyN 7 y( T6 d1 `1 a: W/ l
decryptstr=ObjRSA.Decode(StrMessage) 7 @1 F, ^8 C2 d; K+ K6 D; k5 M1 F
Set ObjRSA = Nothing
) `! x) N' e+ F! q( L- Bend function
@2 @/ C# K( X' o. d%># N* n4 r* E3 B4 ~
===============================================- {2 B i. m0 W Q4 r
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还有一个用于测试这段代码的test.asp
0 {5 T+ T+ @4 F! S2 B有兴趣的自己搭建个IIS测试下
; B* c1 V; l: E0 X- f6 \<!--#INCLUDE FILE="RSA.asp"-->
3 g& ]; X Q/ |- r<%/ e J7 s" o9 S' _$ q9 f M
function Encryptstr(Message) ! T% h$ b1 Z" M& N7 O$ s' ^/ X
Dim LngKeyE
! k8 j3 V) A: t4 WDim LngKeyD
# b7 S" m& ] c# K2 cDim LngKeyN
3 J0 {) U* G' |' B: HDim StrMessage ; A& Q ]. Y) k
Dim ObjRSA
% N9 v! `! w; {, O1 m7 g1 B3 e& x& SLngKeyE = "32823" 6 b) Y% S& U+ n# T! q
LngKeyD = "20643"
n* m& W) E& O! Y% j4 h1 V; @) xLngKeyN = "29893"
: A" F- O6 t2 A+ S0 _StrMessage = Message 8 Z1 _" R/ V$ x( n2 U% F
Set ObjRSA = New clsRSA
1 y1 i1 ]9 L0 v9 L# K4 rObjRSA.PublicKey = LngKeyE * X% p' z$ e& \9 x9 O
ObjRSA.Modulus = LngKeyN
) C* K! O5 P E, S# T! }Encryptstr = ObjRSA.Encode(StrMessage) . S: I H _( m" B
Set ObjRSA = Nothing 1 x: ^! H. n3 u5 H T+ I, ^
end function
6 \4 A7 z) z0 ]% z# h. ffunction decryptstr(Message)
" y: F& D d' b$ r- a1 q$ dDim LngKeyE
" |2 I+ }( H0 I; @! gDim LngKeyD
) c0 B8 H( h9 a* Q2 R9 v: bDim LngKeyN
: |9 L+ {6 g T7 u- ^ aDim StrMessage
0 M" n8 V7 }9 G8 q4 @: E# \( e/ U7 rDim ObjRSA
2 k( L- j& o5 n% Z* v0 bLngKeyE = "32823" ) r$ V- D0 n' X0 H! e% H4 r
LngKeyD = "20643" 0 t# a4 }! J( S* a
LngKeyN = "29893" " l$ X6 x. k& N8 i' O t" E% D0 J
StrMessage = Message
+ a8 v! Q' R* c1 TSet ObjRSA = New clsRSA 2 p# C! B* @+ }: u; V' @
ObjRSA.PrivateKey =LngKeyD
& q% H/ R8 Q: o3 C2 X. N) k8 P3 J3 a$ IObjRSA.Modulus=LngKeyN
. I% x' ~6 l; G3 u9 Y/ G( F$ Cdecryptstr=ObjRSA.Decode(StrMessage)
% p: M/ X6 F( k) r) DSet ObjRSA = Nothing 0 ~7 t' { n7 f" |( y4 p
end function
+ Q) r) R) T: F7 N: ndim last,first ! \$ P# |1 z D9 }4 p, ~. J e
first="!@#$%^&*()" ( v# j; F- \' b3 E9 }
Response.Write "加密前为:"&first 1 ]7 S" z4 ~, }8 O
last=Encryptstr(first) & A1 `8 R0 j8 M7 s+ P
Response.Write "加密后为"&last % u i( j$ j1 W3 u! R
Response.Write "解密后为" &decryptstr(last)
" K+ C1 i2 W4 ?. ]%> ==============================================
: o0 g" ^/ M* n+ g1 r剩下的就是字符的对照表了
2 j6 E j& Y- }( t1 V ?9 \& K& H) d===================字符集================5 c6 i+ H9 F7 T, p; M
1_____6EBB! I/ m- [( e% H$ l
2_____5C1F- B1 J+ H; g, s q+ {/ J0 i7 q; @
3_____4D75% E) X( _/ u# c4 z
4_____26CC
" A# m- ~- s5 u) e+ w5_____4F88
! J5 t: c7 r, Z, T- B- U- k6_____3F4E" Y7 v! D6 y5 b7 j( B3 _( J
7_____0A9D& ?( e: r1 q9 l0 G- T Q4 [' U
8_____1A1C7 D+ [5 x4 t5 R! r( {# {2 P
9_____6D20$ F8 j- z2 ~* a2 @' `' F. E6 }
0_____1089
+ O0 ?$ r. T/ w8 ]- Ca_____0F3E
; w+ F4 _0 e0 r" i# ]7 Hb_____3159
* R: ` a: I" J- X; Wc_____3517
5 ^" ]2 V: Q4 }0 kd_____419C
& ~) o# m) ^, ~1 ~+ o- `9 le_____615C
H7 @0 I- G% F8 {0 u' uf_____556F
* q1 a. _7 t% E- P; T+ Q( z) s7 d; a Dg_____2B7F0 D: f% R! h. D J) O' y+ X
h_____0F9C
9 ~- j$ u- ~* o1 k Mi_____00FA
( N2 K- W0 v w& bj_____5A50
" ?3 ~ n7 a$ Z2 ]5 S' {. yk_____2850
9 {8 O7 y8 t6 L& ]l_____3E7B
* s7 G! F+ t+ h+ J" Rm_____71C5
K& \; @- w" o* E+ r$ {n_____1FC8
# |* {# ?# W0 ko_____74C1
& L; W0 g; N N2 D( yp_____5FB8
1 d7 w" a% |' \9 sq_____6085
% {; s$ P4 ?% Or_____3AC4
. d& w: Q. P, X4 d1 Us_____2F50
8 G' R; {2 G- q/ U ]/ Jt_____36F8 L, b' s( e, E7 U& c% t5 v4 a' [
u_____7010
0 L" E' s/ m: _# wv_____0B42
: n/ @- {! W$ m: gw_____1C7A
8 k; d2 Y3 s' vx_____16F8+ U* x/ [; y, ?
y_____2EE7
1 ?5 s( I& `/ _: @, L. h( M& i, T2 lz_____5CF3$ U y& b% ^! C' F! `2 A
!_____6233
% f1 E- N& `5 n) t5 y8 ~0 \6 J6 q7 d@_____3A45
5 s O/ `% M/ |& P#_____2291$ o7 y) S& i% a- c' e# `
$_____5D5C
4 `0 s6 h- r$ }7 H$ A- \1 P%_____09B9; P/ r( N( O5 V' S6 w
^_____43EA, @) F* O9 {5 F. @
&_____62B90 x6 I8 Q' F! i# P' {1 r3 i K
*_____6301# |2 [( T5 ~$ s: A, C
(_____4659
I4 Z( S4 Z; g1 J)_____5C82 |
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