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原创作者:柔肠寸断 [3.A.S.T] http://www.3ast.com.cm3 W1 t, j8 U0 i% A4 Q: ~2 `1 Q+ j
原始出处:http://www.3ast.com.cm
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看不懂的直接绕过
7 s1 I( s: d7 i. b' b0 u T加密前为:hwy123456* c4 u! W4 q$ u& y( S1 \# l, b
加密后为0F9C1C7A2EE76EBB5C1F4D7526CC4F883F4E
$ V) U4 P8 n8 Q( L: r) j# f) b, X9 m ]5 o
============================================
8 K* H' Y3 n" |$ K* w+ h+ z7 _( O2 f上面是当时自己校内的心情。现在已经解破出来了,分享给大家
9 P+ Y0 S& k" V9 @. d也就不隐瞒大家什么了,这个是国内某知名大学的后台加密算法( c* e/ @- i9 n }4 F# E4 V) z
以下是RSA算法文件; I$ m/ F- C- ~1 G
8 f1 J; m, @& ? r2 X文件名RSA.ASP
0 @) d9 b5 m8 h+ ?: K( O/ ^& q===============================================
8 d1 \# q2 P/ Y2 W<% : {0 K* u# s4 Q7 D; N% L- g' ~
Class clsRSA # a( `3 {7 K& D7 \7 x) r
Public PrivateKey 2 a! Y% X2 w1 F$ j
Public PublicKey
1 j5 O/ x) G8 dPublic Modulus
" R i1 F1 K9 r# D8 iPublic Function Crypt(pLngMessage, pLngKey)
) H" }1 @5 @1 Y* }On Error Resume Next
& z# t9 Y9 F3 cDim lLngMod
& {' z V2 [% i: H2 ]; LDim lLngResult
, O+ Q8 D, G {+ N/ K" o# _6 QDim lLngIndex 8 {# K" h) K) R
If pLngKey Mod 2 = 0 Then 2 E, o4 w5 Z; K8 n
lLngResult = 1
' n F3 I4 l% gFor lLngIndex = 1 To pLngKey / 2 * [% I& K4 e* I( E) [3 P
lLngMod = (pLngMessage ^ 2) Mod Modulus
, q8 g2 i8 z3 `( d7 E' Mod may error on key generation 6 P" v8 e# [, f2 u* }
lLngResult = (lLngMod * lLngResult) Mod Modulus 0 i; |' P3 F; N' ^, F7 w( y9 C7 s
If Err Then Exit Function p( O y+ u s
Next
$ C# T1 r$ y1 x: e& E4 {Else ! E6 U& t/ C( \$ H- C' Y
lLngResult = pLngMessage 0 p7 p# u6 d' W$ `" J, p" H
For lLngIndex = 1 To pLngKey / 2
$ ~; P4 J! J' _3 N- w: x2 p6 r* qlLngMod = (pLngMessage ^ 2) Mod Modulus * k4 R. e" V# A$ H( U. F/ x+ O
On Error Resume Next
, R+ Q% K w5 R! Y& z' Mod may error on key generation t. A: |0 X+ l, z
lLngResult = (lLngMod * lLngResult) Mod Modulus $ I a4 @! `% U+ z8 N$ ^, c
If Err Then Exit Function 2 g8 H# v$ N* ~; }/ r2 D ~$ t$ L
Next
+ B, `7 Z" C. M9 ^End If " O3 F# s( M/ z$ @
Crypt = lLngResult - D! ^6 K8 `6 W2 S% Q# B s
End Function
+ _% `# s2 H* S; t. i5 d7 A/ q3 \- A- E& ~0 l
Public Function Encode(ByVal pStrMessage)
5 u# R ^ w) dDim lLngIndex
( g' X- x8 L7 c" u, X! K+ lDim lLngMaxIndex
+ i5 A/ ^1 T( s: d/ Z2 \Dim lBytAscii
/ u* M* A5 ]! p/ U$ KDim lLngEncrypted 3 G' t% {& e- L
lLngMaxIndex = Len(pStrMessage)
7 D3 L6 U+ B8 }# s& b7 |( WIf lLngMaxIndex = 0 Then Exit Function $ U1 I1 t4 \3 @8 N7 d
For lLngIndex = 1 To lLngMaxIndex " u: X% Z _0 I
lBytAscii = Asc(Mid(pStrMessage, lLngIndex, 1))
. a) B$ j" v: mlLngEncrypted = Crypt(lBytAscii, PublicKey)
: p; M9 r# k6 M# REncode = Encode & NumberToHex(lLngEncrypted, 4)
5 x' k) ?* w: w1 {8 kNext
, T* }, F1 q4 ~: z8 p+ r+ ~# h# vEnd Function 8 t- K2 ?% W! k3 W' W7 {/ R
Public Function Decode(ByVal pStrMessage) % V% ^# C% e! P% u3 N Y _: w
Dim lBytAscii
5 M( I# H1 P. y: D5 }Dim lLngIndex ' |9 G+ D2 k% p; F+ o: w. \) v0 T
Dim lLngMaxIndex + J h& {( J! ?; U" q7 U
Dim lLngEncryptedData # z9 Z \1 O1 s9 `/ R- ]# h
Decode = ""
0 X; L9 j: w4 [2 m6 r+ qlLngMaxIndex = Len(pStrMessage) ; w& T u7 `. ]3 ]
For lLngIndex = 1 To lLngMaxIndex Step 4 . c9 P; l' j, [2 K; R
lLngEncryptedData = HexToNumber(Mid(pStrMessage, lLngIndex, 4))
{5 Q' Y0 o0 |. j6 nlBytAscii = Crypt(lLngEncryptedData, PrivateKey) $ e5 U* J7 ]; I
Decode = Decode & Chr(lBytAscii) * Y6 c' O6 D9 D+ {( I5 E
Next
$ C! H- i) t3 ~5 xEnd Function ) N4 R- }( t( U' B
Private Function NumberToHex(ByRef pLngNumber, ByRef pLngLength)
/ t) s" G3 x$ r$ }+ SNumberToHex = Right(String(pLngLength, "0") & Hex(pLngNumber), pLngLength)
! v" e$ z+ p: q) Y% k" [End Function
4 x% c" W* j/ U$ l6 r x% APrivate Function HexToNumber(ByRef pStrHex) q3 B& Y$ ]. _% e
HexToNumber = CLng("&h" & pStrHex)
6 v( `" N/ n, M& f/ [9 W7 NEnd Function
4 U. P' s9 w$ E9 k+ q6 eEnd Class 7 j# U- B0 [1 I* C& D
function Encryptstr(Message)
9 t* S) G2 f2 q3 uDim LngKeyE
8 X) b2 A2 }( o! F- `; u% U8 sDim LngKeyD
: v l* X, f7 ?$ YDim LngKeyN 4 @5 f. |% {0 c0 m8 w
Dim StrMessage
9 m# g, W6 r, Y2 sDim ObjRSA
" @% s& h6 h1 t: g& ALngKeyE = "32823" . Q/ D' L& U) B# s8 l$ N
LngKeyD = "20643" " M, U1 R" p% C$ U4 o1 i
LngKeyN = "29893"
5 C. d. d: i- A% f, a& |& gStrMessage = Message
- P9 s8 w; H, T. }Set ObjRSA = New clsRSA % M! v, x4 V/ C* L6 {1 Q+ D
ObjRSA.PublicKey = LngKeyE 3 I" _5 o" E/ U. G
ObjRSA.Modulus = LngKeyN 6 E9 R8 G) j( ^" g. S6 k; w
Encryptstr = ObjRSA.Encode(StrMessage)
* w" z/ k! x/ X3 J% m1 nSet ObjRSA = Nothing 2 }& E& F3 h# A' T( f' T# `" z
end function! p# }8 d( t$ t" v/ T) }% p) ]6 P4 x2 v
Function Decryptstr(Message)
o/ l' d3 O8 } yDim LngKeyE
; l/ L N# _1 t9 L8 G* D rDim LngKeyD 6 F( v% C* _) Q
Dim LngKeyN
5 M6 Y4 O( e7 ~Dim StrMessage / [% R. P; [& C
Dim ObjRSA 3 ?4 V& U8 \/ i v% e0 g% p
LngKeyE = "32823"
8 K( g5 C' j8 LLngKeyD = "20643" ; c8 a( g P; l7 k, A; M3 u% |
LngKeyN = "29893"
9 K' N5 B2 p% N3 yStrMessage = Message $ Y0 q; B6 i8 C2 {* M
Set ObjRSA = New clsRSA
+ ]! X' n% y0 s; g5 k9 ~* q1 VObjRSA.PrivateKey =LngKeyD
3 \4 Y5 d& x, I3 T$ D* o dObjRSA.Modulus=LngKeyN ! R) B7 L7 b3 _& m5 d+ ^3 R
decryptstr=ObjRSA.Decode(StrMessage)
3 D! K. Y) j0 p( Z2 @1 i4 g: {Set ObjRSA = Nothing
4 @, Q& |" J! F R2 }1 J3 G; vend function - j+ Q8 y q7 |; _9 {7 q. H2 J
%>
5 n2 S- _' K+ H1 c3 i9 O===============================================
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0 ]0 ~! i! B: I- {1 e0 v+ O- ^: ~还有一个用于测试这段代码的test.asp5 B! {2 N1 S2 }2 [4 b
有兴趣的自己搭建个IIS测试下2 l7 M; k. y- y v9 Z1 `, W
<!--#INCLUDE FILE="RSA.asp"-->
) P, Q3 W- ^2 P! H4 r* s9 H<%! n& N, G2 W* q" O' _( p$ h+ E
function Encryptstr(Message)
( c" Z( g* x' M2 _" U' t+ yDim LngKeyE
0 _2 C$ h/ z" WDim LngKeyD
, n2 D- J" `+ l. s, oDim LngKeyN ; T5 K9 o- `1 P( q4 n1 Y: A: [9 Z
Dim StrMessage ' L& u, \% P% x* |2 I( _
Dim ObjRSA 3 p/ K) \0 |1 o, S, P. M( G
LngKeyE = "32823" / |6 q. u8 o$ R# D& N: S5 p A& e! v
LngKeyD = "20643"
+ l7 O- `+ o+ I A3 t- Z( q' K: kLngKeyN = "29893"
+ Y# n+ m# f' _8 v: T, NStrMessage = Message - U7 R$ u2 O7 Y8 y1 d2 b b5 B
Set ObjRSA = New clsRSA ' ?6 D+ w2 C$ v. q! L; T- W2 s7 b
ObjRSA.PublicKey = LngKeyE 6 k9 c5 k* W1 n( n& i
ObjRSA.Modulus = LngKeyN
, O& P0 J Y1 }Encryptstr = ObjRSA.Encode(StrMessage) 9 o# x+ r1 \6 O% n: ~
Set ObjRSA = Nothing
& m! I* r; M) q/ lend function " p3 c3 }6 }& _% |* ]/ R
function decryptstr(Message)
$ \9 p& p& s! i) ?6 vDim LngKeyE
9 q$ I4 p: r9 L1 c" F8 ?Dim LngKeyD
- b1 f4 N9 b7 j+ G, e! JDim LngKeyN
% G! J) z* O' G1 a5 GDim StrMessage - P% j+ ]* V8 b' E
Dim ObjRSA u' N* I2 F# A; W3 l
LngKeyE = "32823" Z% n& e7 P5 p k% Q
LngKeyD = "20643" $ [) g+ M0 s: r0 D' l' e( v; y
LngKeyN = "29893" 2 L9 i) i- U( f' g% ~" D& Y7 D
StrMessage = Message
* C1 Z5 q- e8 S" [% P7 H6 a7 ISet ObjRSA = New clsRSA
( Q! `, l g. A0 v" E* `( @$ ^+ lObjRSA.PrivateKey =LngKeyD
$ J% H! _5 D; x4 HObjRSA.Modulus=LngKeyN
& R- m( m2 B7 g7 f- h `' O; O: Ndecryptstr=ObjRSA.Decode(StrMessage) : z4 e9 i6 _* b( ^1 u1 x& j: u) ~$ k* G$ B
Set ObjRSA = Nothing 9 @! ?( d8 r p- D6 v
end function * G; _6 `" B# }* a+ a$ ^
dim last,first ' S. d+ G1 c8 [& c. L: ~$ L
first="!@#$%^&*()"
* @( W, k( f5 \; cResponse.Write "加密前为:"&first , J) z% K; S1 U# v
last=Encryptstr(first)
& @, D9 ^- \: F+ y* nResponse.Write "加密后为"&last
; K$ G2 D$ t1 e/ _" b. A w+ \Response.Write "解密后为" &decryptstr(last)
3 |5 B o3 S0 I: h%> ==============================================8 X9 E4 u: G+ {& K2 v d
剩下的就是字符的对照表了
$ [, S+ K$ T" I5 k2 x5 I. T( W===================字符集================
+ w) y, {- m; V1_____6EBB5 `6 J0 B9 L8 Y
2_____5C1F
) w) i1 a0 z! b) ?: C3_____4D75' n" v0 e' a$ D" @1 H1 v/ p$ S: u0 J
4_____26CC
4 k3 R. k& _; r9 J7 |4 {5_____4F88
% L, R G7 ?* R0 L4 P F) g6_____3F4E
- y* Q8 ~6 B2 W% Q6 u1 a7 x, }! r7_____0A9D
( l* ~- w) g2 L/ R. ^ h* h8_____1A1C8 v1 l, J* g. t+ i8 E" v/ b; v
9_____6D20
! [6 ^/ J" y- @9 t0_____1089; Z' g/ s' d" \( J, Y
a_____0F3E
% m1 a |! i& [6 R6 P$ l1 w3 l5 ab_____3159
}1 ~" d5 {/ _6 Jc_____3517
* O1 }0 T! c: G7 U$ Nd_____419C
P( T$ I7 h$ K- j9 k5 }4 S! [3 \e_____615C
Y* x( B( o/ I6 G9 [f_____556F9 u( T5 ^, q* ]8 u/ ~0 ^# N
g_____2B7F
1 Q* f5 T+ u0 q: nh_____0F9C5 Q& |1 A- _3 y9 m- T1 E- O
i_____00FA
% g, k# d$ b7 A4 G1 ^) \5 ?7 J. kj_____5A500 L, ~- e6 p1 A, U( H' A. g
k_____2850
: A* E; |( r; i5 u: kl_____3E7B3 _: T0 V g! U" n( {) G
m_____71C54 g6 i( a# ]( f" t
n_____1FC8
# C1 a0 R; c, u S8 Ko_____74C1
" I }& w! O+ G" p% ?p_____5FB8! r; z9 y& B$ }8 Y) ~2 t
q_____6085 i9 T4 w- G- Q9 p# @8 G
r_____3AC44 Y+ v# V* v3 _2 Y3 z
s_____2F50
& r2 f+ V1 y r' N5 dt_____36F8
$ s& z3 {# [' gu_____7010
$ y5 }0 c: @- W0 D/ ^, O- n) Yv_____0B42
+ w/ ~2 V, F) J; I* u3 cw_____1C7A% ~. X2 {+ I7 `- N* P( ]
x_____16F8
6 @0 B6 d1 i. |+ T" Z9 cy_____2EE7, ?4 G# l- E+ i
z_____5CF3
' C6 ~3 o: i: u/ L5 v, l- u!_____6233
; |; F8 P5 \4 e@_____3A453 z, T- U. a. k+ S) L& }; ^6 r
#_____2291
/ C) ^, |: D' l, G: e. A) Q$_____5D5C# Z3 b: o( o' p; e9 J9 ~
%_____09B9% E/ X1 I; X- X
^_____43EA
+ g \* T! a: h' x5 E, M* @&_____62B9/ `/ r' P% @# V6 k6 J8 r
*_____6301
# s+ v& q6 C$ S(_____4659
- I/ \9 [' R$ t( {- d)_____5C82 |
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